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![]() | 作者: sniper167 [sniper167]
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循环移位,n>0向右移n位,n<0向左移n位 如15896。向右移二位,变为96158 向左移二位,变位89615 main() {unsigned long number; int n; printf("please input the number and n:\n"); scanf ("%ul,%d",&number,&n); if (number<10) {printf("input error!");getch();exit();} if (n>0) {printf("number=%d Move rightwards of %d\n",number,n); right(number,n); } else {printf("number=%d Move leftwards of %d\n",number,n); left(number,-n); } getch(); } void right(unsigned long value,int n) {int k,i; unsigned long m; m=value; k=1; while(m>=10) {k*=10; m=m/10; } for (i=1;i<=n;i++) {value=value/10+(value-value/10*10)*k; } printf("Now,number=%ul\n",value); } void left(unsigned value,int n) {int k,i; unsigned long m; k=1; m=value; while(m>=10) {k*=10; m=m/10; } for (i=1;i<=n;i++) {value=(value-m*k)*10+m; } printf("Now,number=%ul\n",value); } 错误 yiwei.c 18: 与'right'声明中的类型不匹配 错误 yiwei.c 34: 与'left'声明中的类型不匹配 想请286指点,还有没有更好的算法?怎样解决不匹配的错误? 谢谢! |
地主 发表时间: 04-02-28 17:27 |
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unsigned long number; if (number<10) 两句矛盾了。既然是无符号,则全是正的。 |
B1层 发表时间: 04-03-01 12:48 |
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#include <stdio.h> void right(unsigned long value,int n); //声明 void left(unsigned value,int n); void main() { unsigned long number; int n; printf("please input the number and n:\n"); scanf ("%ul,%d",&number,&n); if (number<10) { printf("input error!"); getch(); exit(2); } if (n>0) { printf("number=%d Move rightwards of %d\n",number,n); right(number,n); } else { printf("number=%d Move leftwards of %d\n",number,n); left(number,-n); } getch(); } void right(unsigned long value,int n) { int k,i; unsigned long m; m=value; k=1; while(m>=10) { k*=10; m=m/10; } for (i=1;i<=n;i++) { value=value/10+(value-value/10*10)*k; } printf("Now,number=%ul\n",value); } void left(unsigned value,int n) { int k,i; unsigned long m; k=1; m=value; while(m>=10) { k*=10; m=m/10; } for (i=1;i<=n;i++) { value=(value-m*k)*10+m; } printf("Now,number=%ul\n",value); } |
B2层 发表时间: 04-03-01 13:02 |
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感谢万分 |
B3层 发表时间: 04-03-01 22:06 |
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